![]() Substituting this value of K in the above equation, we have To begin with, when t=0, i=0, hence putting these values in (ii) above, we get Where e is the Napierian logarithmic base = 2.718 and K is constant of integration whose value can be found from the initial known conditions. The applied voltage V must, at any instant, supply not only the ohmic drop iR over the resistance R but must also overcome the e.m.f. We will now investigate the growth of current I through such an inductive circuit. of self-inductance, delays the instantaneous full establishment of current through it. self-inductance and hence, due to the production of the counter e.m.f. It is easily explained by recalling that the coil possesses electrical inertia i.e. It is found that current does not reach its maximum value instantaneously but take some finite time. Let us take the instant of closing switch SW1 as the starting zero time. Derivation of Rise of Current in Inductive Circuit When SW1 is connected to ‘a’ the R-L combination is suddenly put across the voltage of V volt.
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